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74 lines
2.2 KiB
74 lines
2.2 KiB
15 years ago
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/*
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Copyright (C) 2000 Stefan Westerfeld
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stefan@space.twc.de
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This library is free software; you can redistribute it and/or
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modify it under the terms of the GNU Library General Public
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License as published by the Free Software Foundation; either
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version 2 of the License, or (at your option) any later version.
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This library is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Library General Public License for more details.
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You should have received a copy of the GNU Library General Public License
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along with this library; see the file COPYING.LIB. If not, write to
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15 years ago
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the Free Software Foundation, Inc., 51 Franklin Street, Fifth Floor,
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Boston, MA 02110-1301, USA.
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15 years ago
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*/
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#include "aggregation.h"
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#include <iostream>
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using namespace std;
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using namespace Arts;
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class String_impl : virtual public String_skel {
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string _value;
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public:
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void constructor(const std::string& value) { _value = value; }
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string value() { return _value; }
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void value(const std::string& newValue) { _value = newValue; }
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};
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REGISTER_IMPLEMENTATION(String_impl);
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void printall(Arts::Object o, std::string pre = "")
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{
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String s;
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s = DynamicCast(o);
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if(!s.isNull())
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cout << pre << " - " << s.value() << endl;
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vector<string> *children = s._queryChildren();
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vector<string>::iterator i;
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for(i = children->begin(); i != children->end(); i++)
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printall(s._getChild(*i), pre+" ");
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}
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/*
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* Small test case for aggregation
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*
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* The idea behind all this is that you can add children to objects, building
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* a tree (or if you like graph) of objects without the objects knowing anything
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* about this. Aggregation has strong references, that means, the objects you
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* add together in a tree will stay this way, as long as you keep a reference
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* to the root.
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*/
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int main()
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{
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Dispatcher d;
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String s("spreadsheet");
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s._addChild(String("chart"),"child1");
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s._addChild(String("image"),"child2");
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printall(s);
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cout << "deleting \"child1\"" << endl;
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if(!s._removeChild("child1")) cout << "FAIL" << endl;
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printall(s);
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}
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