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249 lines
6.3 KiB
249 lines
6.3 KiB
/***************************************************************************
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* Copyright (C) 2004-2005 by Daniel Clarke *
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* daniel.jc@gmail.com *
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* *
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* This program is free software; you can redistribute it and/or modify *
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* it under the terms of the GNU General Public License as published by *
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* the Free Software Foundation; either version 2 of the License, or *
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* (at your option) any later version. *
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* *
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* This program is distributed in the hope that it will be useful, *
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* but WITHOUT ANY WARRANTY; without even the implied warranty of *
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the *
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* GNU General Public License for more details. *
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* *
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* You should have received a copy of the GNU General Public License *
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* along with this program; if not, write to the *
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* Free Software Foundation, Inc., *
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* 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA. *
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***************************************************************************/
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#include "btreebase.h"
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#include "traverser.h"
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#include "parser.h"
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#include "pic14.h"
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BTreeBase::BTreeBase()
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{
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m_root = 0L;
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}
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void BTreeBase::deleteTree()
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{
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if(m_root) m_root->deleteChildren();
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delete m_root;
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m_root = 0L;
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}
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BTreeBase::~BTreeBase()
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{
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deleteTree();
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}
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void BTreeBase::addNode(BTreeNode *parent, BTreeNode *node, bool left)
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{
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// Debugging lines, remove when expression parsing has been completed.
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//if(!parent) cerr<<"Null parent pointer!\n";
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//if(!node) cerr<<"Null node pointer!\n");
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if(left) parent->setLeft(node);
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else parent->setRight(node);
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}
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void BTreeBase::pruneTree(BTreeNode *root, bool /*conditionalRoot*/)
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{
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Traverser t(root);
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t.descendLeftwardToTerminal();
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bool done = false;
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while(!done)
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{
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//t.descendLeftwardToTerminal();
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if( t.current()->parent() )
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{
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if( t.oppositeNode()->hasChildren() ) pruneTree(t.oppositeNode());
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}
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t.moveToParent();
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if( !t.current()->hasChildren() )
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{
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//if(t.current() == t.root()) done = true;
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if(!t.current()->parent()) done = true;
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continue;
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}
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BTreeNode *l = t.current()->left();
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BTreeNode *r = t.current()->right();
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BTreeNode *n = 0;
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BTreeNode *z = 0;
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// Deal with situations where there are two constants so we want
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// to evaluate at compile time
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if( (l->type() == number && r->type() == number) ) // && !(t.current()==root&&conditionalRoot) )
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{
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if(t.current()->childOp() == Expression::division && r->value() == "0" )
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{
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t.current()->setChildOp(Expression::divbyzero);
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return;
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}
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TQString value = TQString::number(Parser::doArithmetic(l->value().toInt(),r->value().toInt(),t.current()->childOp()));
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t.current()->deleteChildren();
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t.current()->setChildOp(Expression::noop);
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t.current()->setType(number);
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t.current()->setValue(value);
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}
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// Addition and subtraction
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else if(t.current()->childOp() == Expression::addition || t.current()->childOp() == Expression::subtraction)
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{
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// See if one of the nodes is 0, and set n to the node that actually has data,
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// z to the one containing zero.
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bool zero = false;
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if( l->value() == "0" )
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{
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zero = true;
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n = r;
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z = l;
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}
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else if( r->value() == "0" )
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{
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zero = true;
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n = l;
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z = r;
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}
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// Now get rid of the useless nodes
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if(zero)
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{
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BTreeNode *p = t.current(); // save in order to delete after
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replaceNode(p,n);
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t.setCurrent(n);
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// Delete the old nodes
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delete p;
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delete z;
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}
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}
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// Multiplication and division
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else if(t.current()->childOp() == Expression::multiplication || t.current()->childOp() == Expression::division)
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{
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// See if one of the nodes is 0, and set n to the node that actually has data,
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// z to the one containing zero.
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bool zero = false;
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bool one = false;
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if( l->value() == "1" )
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{
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one = true;
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n = r;
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z = l;
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}
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else if( r->value() == "1" )
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{
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one = true;
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n = l;
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z = r;
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}
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if( l->value() == "0" )
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{
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zero = true;
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n = r;
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z = l;
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}
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else if( r->value() == "0" )
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{
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// since we can't call compileError from in this class, we have a special way of handling it:
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// Leave the children as they are, and set childOp to divbyzero
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if( t.current()->childOp() == Expression::division )
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{
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t.current()->setChildOp(Expression::divbyzero);
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return; // no point doing any more since we are going to raise a compileError later anyway.
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}
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zero = true;
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n = l;
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z = r;
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}
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// Now get rid of the useless nodes
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if(one)
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{
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BTreeNode *p = t.current(); // save in order to delete after
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replaceNode(p,n);
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t.setCurrent(n);
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// Delete the old nodes
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delete p;
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delete z;
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}
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if(zero)
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{
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BTreeNode *p = t.current();
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p->deleteChildren();
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p->setChildOp(Expression::noop);
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p->setType(number);
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p->setValue("0");
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}
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}
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else if( t.current()->childOp() == Expression::bwand || t.current()->childOp() == Expression::bwor || t.current()->childOp() == Expression::bwxor )
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{
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bool zero = false;
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if( l->value() == "0" )
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{
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zero = true;
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n = r;
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z = l;
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}
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else if( r->value() == "0" )
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{
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zero = true;
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n = l;
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z = r;
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}
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// Now get rid of the useless nodes
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if(zero)
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{
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BTreeNode *p = t.current();
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TQString value;
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if( p->childOp() == Expression::bwand )
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{
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value = "0";
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p->deleteChildren();
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p->setChildOp(Expression::noop);
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p->setType(number);
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}
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if( p->childOp() == Expression::bwor || p->childOp() == Expression::bwxor )
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{
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value = n->value();
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BTreeNode *p = t.current(); // save in order to delete after
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replaceNode(p,n);
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t.setCurrent(n);
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// Delete the old nodes
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delete p;
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delete z;
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}
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p->setValue(value);
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}
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}
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if(!t.current()->parent() || t.current() == root) done = true;
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else
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{
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}
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}
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}
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void BTreeBase::replaceNode(BTreeNode *node, BTreeNode *replacement)
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{
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// (This works under the assumption that a node is not linked to two places at once).
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if( !node->parent() )
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{
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setRoot(replacement);
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replacement->setParent(0L);
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return;
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}
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if( node->parent()->left() == node ) node->parent()->setLeft(replacement);
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if( node->parent()->right() == node ) node->parent()->setRight(replacement);
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}
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